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01-05-2008
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awk system date with -d option
Hi
I get problems when using the following command : Code:
cat logs | awk -F";" '{ system("date -d "1970-01-01 UTC+0100 $1 seconds""); }'
date: date invalide `1968641199401200'
date: date invalide `1968641199381709'
Code:
cat logs 1199401200;a 1199381709;b Any idea ? Thx Last edited by arag0rn; 01-05-2008 at 07:48 AM. 
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01-05-2008
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Code:
while IFS=";" read a b
do
date -d "1970-01-01 UTC+0100 $a seconds"
done < file
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01-05-2008
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Thanx but This is not what i want to do
thx for this idea but it does not work for me
 I made something that gives the same output your code should give but this is not what i am searching for : Code:
for mytimestamp in $(cat logs| awk -F";" '{ print $1; }'); do echo $(date -d “1970-01-01 UTC+0100 $mytimestamp seconds”); done
Last edited by arag0rn; 01-05-2008 at 07:49 AM.
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01-05-2008
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If you have GAWK you can use the strftime function or you can fit the script of gostdog74 like:
Code:
while IFS=";" read a b
do
echo $(date -d "1970-01-01 UTC+0100 $a seconds")";"$b
done < file
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