How to check a word position in a file ? - Shell Programming and Scripting

tibo · #1 (**permalink**) 01-03-2008

Hello everybody,
I have a file like this : "window 1 truck 3 duck 2... fire 1... etc..." and I would like to print the following number of a word I am searching for. (For example here, if I search for the word "fire", I will print "1")
Thank you for your help !

shamrock · #2 (**permalink**) 01-03-2008

Quote:

Originally Posted by tibo

Hello everybody,
I have a file like this : "window 1 truck 3 duck 2... fire 1... etc..." and I would like to print the following number of a word I am searching for. (For example here, if I search for the word "fire", I will print "1")
Thank you for your help !

Code:

sed 's/.* fire \([0-9][0-9]*\) .*/\1/' file

ghostdog74 · #3 (**permalink**) 01-03-2008

Code:

s="window 1 truck 3 duck 2... fire 1"
f=0
for i in $s;  
do  
    if [ $f -eq 1 ];then    
      echo "Found number $i"
    fi
    case $i in 
      fire) f=1 ; continue;;
    esac;  
done

rikxik · #4 (**permalink**) 01-03-2008

Quote:

Originally Posted by shamrock

Code:

sed 's/.* fire \([0-9][0-9]*\) .*/\1/' file

Doesn't work here:

Code:

$ uname -a
SunOS db012a 5.8 Generic_117350-35 sun4us sparc FJSV,GPUZC-M
$ which sed
/usr/bin/sed
$ cat file
window 1 truck 3 duck 2 fire 1
$ sed 's/.* fire \([0-9][0-9]*\) .*/\1/' file
window 1 truck 3 duck 2 fire 1

ghostdog74 · #5 (**permalink**) 01-03-2008

Quote:

Originally Posted by rikxik

Doesn't work here:

Code:

$ uname -a
SunOS db012a 5.8 Generic_117350-35 sun4us sparc FJSV,GPUZC-M
$ which sed
/usr/bin/sed
$ cat file
window 1 truck 3 duck 2 fire 1
$ sed 's/.* fire \([0-9][0-9]*\) .*/\1/' file
window 1 truck 3 duck 2 fire 1

This is because in your sample file, after the "1", there is no space.
The sed statement has a <space> after the \) bracket. It should be

Code:

# sed 's/.* fire \([0-9][0-9]*\).*/\1/' file
1

for your case of sample file

rikxik · #6 (**permalink**) 01-03-2008

Then lets do this:

Code:

sed 's/ *.*fire \([0-9][0-9]*\).*/\1/' file

Works with/without leading/trailing spaces.

shamrock · #7 (**permalink**) 01-03-2008

Quote:

Originally Posted by rikxik

Then lets do this:

Code:

sed 's/ *.*fire \([0-9][0-9]*\).*/\1/' file

Works with/without leading/trailing spaces.

But the above pattern will also catch words like backfire, spitfire etc...

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