Modify shell variables with AWK - Shell Programming and Scripting

Santi · #1 12-26-2007

Dear Folks,

I have a command output something like:

Quote:

# gsmctl -d /dev/ttyS0 pin sig
<PIN0> READY
<SIG0> 31

And I want to store PIN0 and SIG0 in two shell variables, now I do a double awk:

Code:

PIN=`gsmctl -d /dev/ttyS0 pin sig | awk '/PIN0/ { print $2}'` 
SIG=`gsmctl -d /dev/ttyS0 pin sig | awk '/SIG0/ { print $2}'`

It's possible to modify two shell variables only calling one time to AWK? Perhaps defining two shell variables and modifying in a AWK block.. thanks!!

Regards,

fpmurphy · #2 12-26-2007

Code:

/PIN0/  { printf "PIN=%s\n", $2  }
/SIG0/  { printf "SIG=%s\n", $2  }

Code:

$ eval `gsmctl -d /dev/ttyS0 pin sig | awk -f awkfile`
$ echo $PIN $SIG
READY 31

Santi · #3 12-26-2007

fpmurphy, thanks for your reply ;-)

I want to use only one script/file.. using awk -f I need at least two files, is there any solution to make this only with one script? perhaps using another way instead of awk? Thanks!!

Regards,

shamrock · #4 12-26-2007

Quote:

Originally Posted by Santi

I want to use only one script/file.. using awk -f I need at least two files, is there any solution to make this only with one script? perhaps using another way instead of awk?

Regards,

Code:

gsmctl -d /dev/ttyS0 pin s | xargs | read X PIN Y SIG
echo $PIN
echo $SIG

rikxik · #5 12-26-2007

Quote:

Originally Posted by shamrock

Code:

gsmctl -d /dev/ttyS0 pin s | xargs | read X PIN Y SIG
echo $PIN
echo $SIG

Not nitpicking - the above does not work with sh/bash - only in ksh. This should work with all three:

Code:

set `gsmctl -d /dev/ttyS0 pin s |awk '{print $2}'`
echo $1 $2

HTH

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