Is it possible to pass variable from awk to shell script

user_prady · #1 (**permalink**) 12-18-2007

Hello experts,

can I return a value from gawk to a shell script ?

My script as follows,

Code:


#Here I want the num[1] value to shell script so that I can use later 
gawk ' 
{
        split($0,num,",");
        print num[1]
}'
gawk -v no=$number '{print no}'

file1

Code:

000000,CB1F,0,0,0,0,1,0,1

I want to return the variable num[1] from one gawk to shell script or to other gawk block.

Please help ....

sysgate · #2 (**permalink**) 12-18-2007

I scrolled down to the bottom of the page, and I found similar topic, HTH.

user_prady · #3 (**permalink**) 12-18-2007

Quote:

Originally Posted by sysgate

I scrolled down to the bottom of the page, and I found similar topic, HTH.

Thank you for the reply .

Yeah I saw that thread before I posted this thread ,
but I found nothing useful for my code or my need there. Thats why I posted my problem here.

Regards,
User_prady

matrixmadhan · #4 (**permalink**) 12-18-2007

something like this,

Code:

var=`awk '{ split($0, num, ","); print num[1] }' a`
echo $var

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