Show result only if number is greater then

umen · #1 (**permalink**) 12-05-2007

Hello all
Im trying to write one liner that will show me results only if the result of the expression is greater then 0
For example:
I do :

PHP Code:


			
find . -name "*.dsp" | xargs grep -c SecurityHandler 

the result are : 

 ./foo/blah/a.dsp:0

./foo/blah1/b.dsp:1

./foo/blah2/c.dsp:2

./foo/blah3/d.dsp:0

Now I like to print only dsp's that the word " SecurityHandler" is more then 0
How can it be done?

matrixmadhan · #2 (**permalink**) 12-05-2007

Code:

find . -name "*.dsp" | xargs grep -c SecurityHandler  | awk ' !/:0/ { print }'

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