cannot get logic for concatenation awk

user_prady · #1 (**permalink**) 12-04-2007

Hello friends,

I have a problem in printing an array..

Example if my array line contains 4 elements like following
line[1]=0002 , line[2]=202200, line[3]=200002, line[4]= 300313

Now

Code:

 one = sprintf line[1] line[2] line[3] line[4]

gus2000 · #2 (**permalink**) 12-04-2007

Code:

awk 'BEGIN{a[1]="abc";a[2]="def";print length(a)}'
2

user_prady · #3 (**permalink**) 12-04-2007

Quote:

Originally Posted by gus2000

Code:

awk 'BEGIN{a[1]="abc";a[2]="def";print length(a)}'
2

Once you know the number of elements, you can use a for loop.

Thanks for the reply ,, Yes I do know how many elements are in the array,
but my problem is to print it in one variable

suppose if my number of elements in the array is 3 ,then my commnad should look like this

Code:

input = sprint line[1] line[2] line[3]

ghostdog74 · #4 (**permalink**) 12-04-2007

Code:

awk 'BEGIN { 
  line[1]="a"
  line[2]="b"
  line[3]="c"
  for ( i=1;i<=3;i++) {
    result=result""line[i]
  }
  print result
}'

user_prady · #5 (**permalink**) 12-04-2007

Quote:

Originally Posted by ghostdog74

Code:

awk 'BEGIN { 
  line[1]="a"
  line[2]="b"
  line[3]="c"
  for ( i=1;i<=3;i++) {
    result=result""line[i]
  }
  print result
}'

Thank you I got that.. Many many thanks ..

user_prady · #6 (**permalink**) 12-04-2007

Quote:

Originally Posted by ghostdog74

Code:

awk 'BEGIN { 
  line[1]="a"
  line[2]="b"
  line[3]="c"
  for ( i=1;i<=3;i++) {
    result=result""line[i]
  }
  print result
}'

Thanks I did like this

Code:

		 input = ""
		 for (i=1 ; i < j ; i ++){
		   input = sprint input "" line[i]
		 }

ghostdog74 · #7 (**permalink**) 12-04-2007

Quote:

Originally Posted by user_prady

Thanks I did like this

Code:

		 input = ""
		 for (i=1 ; i < j ; i ++){
		   input = sprint input "" line[i]
		 }

no need : input=""
what is sprint?

input = input "" line[i] should suffice.

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