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11-23-2007
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print a line containing word in a column using grep
hi,
how to print a row which contains a perticular word in its third column using grep, cut, or any thing else. thanks |
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11-23-2007
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please post it with samples....
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11-23-2007
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awk '{if ($3 == "pattern") print $0}' your-file.txt
If the delimiter is something else like ":", awk -F ':' '{if ($3 == "pattern") print $0}' your-file.txt |
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