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11-20-2007
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passing a list of dynamic names to a "PS" command in shell script?
Hi,
I am new to shell script. This is my first post .I have written a small script which returns list of names starts with "ram" in /etc/passwd .Here is that:- #!/bin/ksh NAME_LIST="name_list.txt" cat /dev/null > $NAME_LIST evalcmd="cat /etc/passwd | grep "^ram?*" | cut -d: -f1" eval $evalcmd > $NAME_LIST 2>&1 echo $? if [[ $? -ne 0 ]] then echo "Failed to create list of names"; else echo "List of names are created successfully"; fi The thing is that i need to pass these dynamic names from /etc/passwd to a "ps" command like:- ps -o user,fname -U ram,ramdev1,ramdev2,ramdev3 Since i cannot hardcode the names like ram,ramdev1,ramdev2,etc i need to pass these names in a single command. something like:- cat /etc/passwd | grep "^ram?*" | cut -d: -f1| ps --o user,fname -U <dynamic variable which fetches the whole name in /etc/passwd> Since i am pretty much new to shellscript.Please do help me on this. This is really urgent to be delivered. Hence pls. do the needful. Thanx, Sachin 
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11-20-2007
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No replies... Pls. do help me in this. It is really urgent.
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11-20-2007
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What shell / OS?
If you're using bash, you should be able to get away with something like: Code:
#! /bin/bash
typeset -i n=0
typeset -a names
oldifs="$IFS"
IFS=:
while read passwdname _; do
[[ $passwdname == *a* ]] && names[n++]=$passwdname
done </etc/passwd
IFS="$oldifs"
names=${names[*]}
ps --o user,fname -U ${names// /,}
Code:
ps --o user,fname | gawk '/^[^ ]*ram/{print $1}'
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