Using find command with awk or basename

sam_78_nyc · #1 (**permalink**) 11-05-2007

Hi,
I am using the following command to extract any log files that are older than 3 days using the following command.

find DIR/LOGDIR -type f -mtime +3 |grep LOG > log_list.out
The results are
DIR/LOGDIR/1.LOG
DIR/LOGDIR/2.LOG
DIR/LOGDIR/3.LOG
DIR/LOGDIR/4.LOG

How do inculde (basename or awk ??) to extract just the file name instead of the complete directory like in log_list.out file.
1.LOG
2.LOG
3.LOG
4.LOG

Thanks all.

aigles · #2 (**permalink**) 11-05-2007

You can do something like that :

Code:

find DIR/LOGDIR -type f -mtime +3 -name '*LOG*' | sed 's_.*/__'  > log_list.out

Jean-Pierre.

sam_78_nyc · #3 (**permalink**) 11-05-2007

Great..
Thanks again..

gus2000 · #4 (**permalink**) 11-05-2007

You could also do this:

Code:

find DIR/LOGDIR -type f -mtime +3 -name '*LOG*' -exec basename {} \;

but this runs "basename" for each file. The "sed" command above is probably several hundred milliseconds faster.

ghostdog74 · #5 (**permalink**) 11-05-2007

if you have GNU find

Code:

find /path -type f -mtime +3 -name '*LOG*'  -printf "%f\n"

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