Hi,

My script will take a input file as a parameter(which is not mandatory) and also an option.
ksh my_script.sh <inputfile> [-n]
The option -n I have given is no way related to the input file.

Now the problem here is when i execute the script specifying the input file and the option(the way as mentioned above), the option part of the code is not working resulting me with no action.
But when i execute the script in this way, I am getting my desired output
ksh my_script.sh -n <inputfile>
But this is not the way i should mention them.

Why the option given at the end is not performing its action.? Is it a rule for getopts or problem with my code?

Please help me regarding this.

Sample code:

#! /bin/ksh
while getopts 'n' option
do
case "$option" in
n)echo "option is n"
;;

?) echo " Bad option specified...."
;;
esac
done

shift `expr $OPTIND - 1`
INPUTFILE=$1
echo $INPUTFILE

Thanks in advance,
Chella