Extract if pattern matches

Raynon · #1 (**permalink**) 10-19-2007

Hi All,

I have an input below. I tried to use the awk below but it seems that it ;s not working. Can anybody help ?
My concept here is to find the 2nd field of the last occurrence of such pattern " ** XXX ccc ccc cc cc ccc 2007 " . In this case, the 2nd field is " XXX ". With this "XXX" term stored as a variable, i want to print out the all lines with 2nd field having " XXX " term and its subsequent lines containing terms matching with " k= ". Expected output are highlighted as bold red in the input.

Input:

wwwwww
0999 k= 1
wwwwww
** XXX ccc ccc cc cc ccc 2007
wwwwww
wwwwww
0001 k= 1
wwwwww
0002 k= 1
** abc ccc cc cc cc cc 2007
wwwwww
0001 k= 1
wwwwww
0002 k= 1
wwwwww
wwwwww
0003 k= 1
wwwwww
** XXX ccc ccc cc cc ccc 2007
wwwwww
0003 k= 1
wwwwww
0004 k= 1
0005 k= 1

Output:

** XXX ccc ccc cc cc ccc 2007
0001 k= 1
0002 k= 1
** XXX ccc ccc cc cc ccc 2007
0003 k= 1
0004 k= 1
0005 k= 1

My AWK code:

Code:

$NF == "2007" && $1 == "**" && NF == "8" {Field2 = $2}

$1 == "**" && $8 == "2007" && $2 == Field2   {
print ;
flag = 1;
next;
}
flag == 1 && $2 ~ /k=/ {print}

$1 == "**" && $8 == "2007" && $2 != Field2 {flag = 0}

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