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Old 10-11-2007
fedora fedora is offline
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regex to delete multiple blank lines in a file?

can't figure out a way to delete multiple empty lines but keep single empty lines in a file, file is like this
#cat file
1

2

3



4

5
6
-

What I want is
1

2

3

4

5
6
--

any idea?
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Old 10-11-2007
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Code:
sed '/^$/d;G' myFile
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Old 10-11-2007
fedora fedora is offline
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thanks for the answer, but by doing this, you also ADD a empty line between
5 and 6, which before has no empty line between.

5
6

not
5

6



Quote:
Originally Posted by vgersh99 View Post
Code:
sed '/^$/d;G' myFile
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Old 10-11-2007
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Code:
awk 1 RS= ORS="\n\n" filename
Use nawk or /usr/xpg4/bin/awk on Solaris.
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Old 10-11-2007
fedora fedora is offline
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Tjhis is awesome!

Can you explain a little bit what the argument "1" does here?

Quote:
Originally Posted by radoulov View Post
Code:
awk 1 RS= ORS="\n\n" filename
Use nawk or /usr/xpg4/bin/awk on Solaris.
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Old 10-11-2007
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Sure:

everything <>0 in awk is true (you can use whatever you want: 1,2 ... 42 ...), true means use default action, which is print the current record.

You could use this, if you prefer:

Code:
awk -- -42 RS= ORS="\n\n" filename
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Old 10-11-2007
fedora fedora is offline
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Thanks again!

Quote:
Originally Posted by radoulov View Post
Sure:

everything <>0 in awk is true (you can use whatever you want: 1,2 ... 42 ...), true means use default action, which is print the current record.

You could use this, if you prefer:

Code:
awk -- -42 RS= ORS="\n\n" filename
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