FOR loop problem: Kindly Help

okdev · #1 (**permalink**) 10-04-2007

Hello Friends,

I have file called reference.txt which looks like below,

Quote:

columns are been formed by delimiter "|" as shown. I am required to scan whole file line by line & compare 1st 2 columns with new name (ex. ferrari) & new version (2.1).

CODE PURPOSE: whnever new project formed compare if it already exists & compare if version updated.

My Code

Quote:

for file in $(cat reference.txt);do
if [[ `echo $file | cut -d ',' -f1` == $PROJECT ]];then
echo "Project Matched"
if [[ `echo $file | cut -d ',' -f2` == $VERSION ]];then
echo "Project & Version Matched"
else
echo "Project Matched but Version Revised"
fi
else
echo "Complete New Project"
fi
echo "$n"
let "n += 1"
done

By executing my code i am finding,
1. its looping for 19 times instead of looping for only 3 times. & providing 3 output for 3 rows.

Kindly help. Thanks a lot.

Ygor · #2 (**permalink**) 10-04-2007

Perhaps try something like this....

Code:

oldIFS="$IFS"
IFS='|'
while read f1 f2 etc
do
   echo do something with $f1 and $f2
done < reference.txt
IFS="$oldIFS"

okdev · #3 (**permalink**) 10-04-2007

Sir thanks a lot for this quick solution. It absolutely gonna help. But stay connected.. if i need some more help!!!

Thanks

okdev · #4 (**permalink**) 10-05-2007

Once i find PROJECT matched & project VERSION matched. I am supposed to update $f3 & $f4 (3rd & 4th field) of same file.

Example:
reference.txt

Quote:

New Project with following variables (I have)

Quote:

PROJECT=ferrari12
VERSION=4.0
LABLE=ferrari12-1.1.25

Reference.txt should look like follwing.

Quote:

Code:

Quote:

#!/bin/sh

PROJECT=ferrari12
VERSION=4.0
LABLE=ferrari12-1.1.25

n=1 # Line Number

oldIFS="$IFS"
IFS='|'
while read f1 f2 f3 etc
do
if [ $f1 == $PROJECT ];then
echo "Line $n: Project Matched"
if [ $f2 == $VERSION ];then
echo " Version Matched"
sed 's/$f3/$LABLE/' # Lable Replaced
else
echo " Version Not Matched"
fi
else
echo "Line $n: New Project"
fi
let "n += 1"
done < reference.txt
IFS="$oldIFS"

some how sed is not working for me there to replace lable. Do you have some logic to fit in this loop.

Please Help! Thanks

okdev · #5 (**permalink**) 10-06-2007

People Please Help me out.
Thanks

drl · #6 (**permalink**) 10-06-2007

Hi.

Use double quotes in this situation -- single quotes do not allow variable expansion:

Code:

sed 's/$f3/$LABLE/' # Lable Replaced

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