Cut Number which appear before a delimiter

Raynon · #1 (**permalink**) 09-30-2007

Hi All,

How can i use the cut option to only output the number of rows, which is 2 is this case ? Pls note that the number of digit before the delimiter ":" is always varying.

$ grep -n uuu xxx
2:** xxx yyy gg 44 tt uuu 2007
$

manas_ranjan · #2 (**permalink**) 09-30-2007

if i understood clearly , u want to print the the record number which is matched by your pattern thru grep, ....then please try the following one........

echo `grep -n uuu xxx` | cut -d":" -f1

Raynon · #3 (**permalink**) 09-30-2007

Hi manas_ranjan,

That's cool.

Can you explain your cut code ?
what does the -f1 mean ?

Code:

cut -d":" -f1

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