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09-20-2007
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Code:
shouldbe=88
awk -v e=$shouldbe '{ if(length($0) != e){print "bad line ", NR} ' filename
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09-20-2007
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Use nawk or /usr/xpg4/bin/awk on Solaris:
Code:
awk 'FNR==1{len=length;next}
length!=len{printf "Check file %s,record %d\n",FILENAME,FNR}' filename[s]
P.S. For portability use length($0). |
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11-08-2007
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check position of end of line for some specific lines
Have to check in a file that the lines starting with 620 and 705
are ending at same posiotin. 82012345 62023232323 70523949558 62023255454 9999 In the above lines, i have to check the lines starting with 620 and 705 are having the length 94. Can anyone help. Immediate response is very much appriciated. |
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11-08-2007
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Use the command given above but change the awk to only look at the relevant lines by doing the following:
awk -v e=$shouldbe '{ /^(620|705)/ if(length($0) != e){print "bad line ", NR} ' filename Should work |
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11-08-2007
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check position of end of line for some specific lines
Thankyou very much for your immediate response.
But its giving some syntax error. this is what i used. shouldbe=94 srcFile=$1 awk -v e=$shouldbe '{ /^(620|705)/ if(length($0) != e){print "bad line ", NR} }' $srcFile The error is below ============== syntax error The source line is 1. The error context is { /^(620|705)/ >>> if <<< (length($0) != e){print "bad line ", NR} } awk: The statement cannot be correctly parsed. The source line is 1. Can you please correct it? |
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