to print number one less than actual number - Shell Programming and Scripting

cdfd123 · #1 (**permalink**) 09-06-2007

suppose we have a file which contains
34
45
56
77
55
66
54
67

so output shud be like
33
44
55
76
54
65
53
66

Nidhi2177 · #2 (**permalink**) 09-06-2007

file_no's content are
34
45
56
77
55
66
54
67

tempfile=file_no
for number in `cat $tempfile`
do
number=$((number-1))
echo $number
done

radoulov · #3 (**permalink**) 09-06-2007

Code:

zsh 4.3.4% cat file
34
45
56
77
55
66
54
67
zsh 4.3.4% eval printf "%d\\\n" $(printf "\$((%d-1)) " $(<file))
33
44
55
76
54
65
53
66

or:

Code:

zsh 4.3.4% awk '$1=$1-1' file
33
44
55
76
54
65
53
66

namishtiwari · #4 (**permalink**) 09-06-2007

or you can do something like this

for line in `cat $file`
do
line=`expr $line - 1`
echo $line
done

Thanks
Namish

manas_ranjan · #5 (**permalink**) 09-06-2007

Hey please try this one,

awk ' { printf ("%d\n", $0-1) } ' <<File Name>>

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