![]() |
|
|
google unix.com
|
|||||||
| Forums | Register | Forum Rules | Links | Albums | FAQ | Members List | Calendar | Search | Today's Posts | Mark Forums Read |
| Shell Programming and Scripting Post questions about KSH, CSH, SH, BASH, PERL, PHP, SED, AWK and OTHER shell scripts and shell scripting languages here. |
More UNIX and Linux Forum Topics You Might Find Helpful
|
||||
| Thread | Thread Starter | Forum | Replies | Last Post |
| Double quotes or single quotes when using ssh? | password636 | Shell Programming and Scripting | 3 | 05-29-2008 09:52 PM |
| Escaping the * character in ksh. | arvindcgi | Shell Programming and Scripting | 6 | 05-19-2008 10:50 AM |
| escaping double-quotes inside the script? | GKnight | Shell Programming and Scripting | 3 | 05-05-2008 06:35 PM |
| Escaping '*' in Bash | rkshukla14 | Shell Programming and Scripting | 7 | 04-05-2007 12:45 AM |
| Incorrect Directory Name | jand102821 | UNIX for Dummies Questions & Answers | 1 | 06-19-2002 05:35 PM |
|
|
LinkBack | Thread Tools | Search this Thread | Rate Thread | Display Modes |
|
||||
|
incorrect quotes/escaping?
Hi all, i have a perl script. from within the perl script, i am calling a system command which i need to pass in a perl variable. but the variable substitution does not seems to happen. would like to find out where is the missing escape character or extra quotes;or what is my mistake.
Code:
#!/usr/bin/perl -w
$community="public";
$result=system("snmpwalk -v 2c -c $community localhost system");
|
| Bookmarks |
| Tags |
| perl, snmpwalk |
| Thread Tools | Search this Thread |
| Display Modes | Rate This Thread |
|
|