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08-30-2007
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Script lines of a Log Files
I am creating a script that will look through a log file and print the previous days entries. However I do not want the complete line of the entry.
A single line of the log file is as follows: Aug 30 06:35:08 trnwvltfit1 /usr/lib/snmp/snmpdx: [ID 702911 daemon.error] Agent snmpd appeared dead but responded to ping I am using the date of the line to determine which lines to print. However, I am only trying to print the parts of the line that are NOT highlighted in red. I have no knowledge of how long the line may be. How can this be done? So far I have: Code:
$cat messages.log | grep "Aug 30" | |
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