Content of Content of a variable!

jaduks · #1 (**permalink**) 08-26-2007

I got a sample BASH script like this :

$ cat test
MYVAR=$1
DUMMY1="This is tricky"
DUMMY2=24
echo $[$MYVAR]

$ ./test DUMMY1
./test: line 5: This is tricky: syntax error in expression (error token is "is tricky")
**I was expecting the output as "This is tricky", ah! but no luck

**But this works fine for intergers, no issues :-)
$ ./test DUMMY2
24

Could anyone guide me how to get the string in DUMMY1(i.e "This is tricky") through MYVAR? Please

navojit dutta · #2 (**permalink**) 08-27-2007

Instead of echo $[$MYVAR], you can use : echo ${!MYVAR}...It will be working fine.

jaduks · #3 (**permalink**) 08-27-2007

Navojit, that worked for me :-) Thanks a lot

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