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08-26-2007
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Content of Content of a variable!
I got a sample BASH script like this :
$ cat test MYVAR=$1 DUMMY1="This is tricky" DUMMY2=24 echo $[$MYVAR] $ ./test DUMMY1 ./test: line 5: This is tricky: syntax error in expression (error token is "is tricky") **I was expecting the output as "This is tricky", ah! but no luck **But this works fine for intergers, no issues :-) $ ./test DUMMY2 24 Could anyone guide me how to get the string in DUMMY1(i.e "This is tricky") through MYVAR? Please 
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08-26-2007
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Instead of echo $[$MYVAR], you can use : echo ${!MYVAR}...It will be working fine.
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