Hi,

I really need some help with GREP searching...

I need to find all occurances of a file reference and remove two characters from the end of the reference. For example, here are a few lines showing the text:

<image file="STRAIGHT_004CR.jpg" ALT="STRAIGHT_004CR.jpg" />
<image file="STRAIGHT_006CR.jpg" ALT="STRAIGHT_006CR.jpg" />
<image file="STRAIGHT_007CR.jpg" ALT="STRAIGHT_007CR.jpg" />

And they then need to look like:

<image file="STRAIGHT_004.jpg" ALT="STRAIGHT_004.jpg" />
<image file="STRAIGHT_006.jpg" ALT="STRAIGHT_006.jpg" />
<image file="STRAIGHT_007.jpg" ALT="STRAIGHT_007.jpg" />

I think I've written the correct search query which I think is:

_\d{3}\D\D

But I have no idea how to write the replacement string to remove the additional letters at the end of the string of 3 numbers and leave everything else in tact...

ANy help would be much appreciated...

Thanks

Steve.

Hi,

try using :

sed. sed 's/CR.jpg/.jpg/g'

But make sure you have a backup of the file.
regards

Thanks for this...

Not sure i was very clear before, the text I need to replace has the last two letters vary so I can't specificaly request a change on a specific set of characters like 'CR'.

The text string I need to replace is made up of varying 3 digits and then 2 letters like:

000XX

But I need to remove the two letters in each instance but preserve the rest of the text around the string as in the example:

<image file="STRAIGHT_000XX.jpg" ALT="STRAIGHT_000XX.jpg" />

needs to look like:

<image file="STRAIGHT_000.jpg" ALT="STRAIGHT_000.jpg" />

I am using a text editing program to do this which supports GREP find and replace so need to know the GREP search query string which I think is _\d{3}\D\D and then the Replacement string which will remove the two letters at the end of the text which it finds...

Sorry to be a pain...

Thanks.

sed 's/\(.*\)\(..\)\(....\)/\1\3/' filename

sed 's/[A-Z][A-Z].jpg/.jpg/g' <file-name>

Thanks guys...!

Should work a treat...!

All the best!!