Variable in Variable name?

rorey_breaker · #1 (**permalink**) 08-25-2007

Hi I am writing a script to show the current users and their current processes along with their actual name, tty, pid etc...

I am thinking the best method is to cut the infomation from the who, finger and w commands using a temp file to store and then pull the info from.

Inorder to set the unsernames to variables ($user1, user2...) I am attempting to set a variable as follows:

$user${pos}=$1

pos is simply one and is set previously in the code, but the problem lies with a command not found error which comes after this statement.

Any ideas?? -- thanks

Also anyone know how i can copy the code from vi so I can paste it into my browser?? cheers

aigles · #2 (**permalink**) 08-25-2007

You must use the eval command :

Code:

eval user${pos}=$1

Instead of using variables user1, user2,... you can use an array :

Code:

${user[$pos]}=$1

Jean-Pierre.

rorey_breaker · #3 (**permalink**) 08-26-2007

I will give that go - Thanks for your help!

More UNIX and Linux Forum Topics You Might Find Helpful
Thread	Thread Starter	Forum	Replies	Last Post
passing a variable inside a variable to a function	KingVikram	UNIX for Dummies Questions & Answers	2	01-14-2008 08:28 PM
How to replace variable inside the variable	mani_um	Shell Programming and Scripting	31	08-09-2007 11:56 PM
Replace variable with a user defined variable	ce124	Shell Programming and Scripting	1	04-15-2007 03:56 PM
Export command giving Variable Name vs the Value set for the Variable	ParNone	UNIX for Dummies Questions & Answers	2	04-03-2006 12:43 PM
ksh: A part of variable A's name is inside of variable B, how to update A?	pa3be	Shell Programming and Scripting	4	03-30-2005 12:29 PM

Thread Tools	Search this Thread
Show Printable Version Email this Page	Search this Thread: Advanced Search
Display Modes	Rate This Thread
Switch to Linear Mode Hybrid Mode Switch to Threaded Mode	Rate This Thread:


	Powered by