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08-08-2007
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Command to get File Timestamp including seconds [Aix 5.3]
Is there a command (like ls -l) to get the file time stamp including seconds? The ls -l gives only the HH:MM, No SS
I don't have a C compiler to call stat() I don't a command like stat too. Please help. |
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08-08-2007
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As far as I know only GNU ls supports this
Code:
$ ls -l total 488 -rw-r--r-- 1 me mygroup 234329 Aug 7 22:58 curl-7.15.5-2.el5.x86_64.rpm -rw-r--r-- 1 me mygroup 253488 Aug 7 23:10 curl-7.16.4-1.fc8.x86_64.rpm $ ls -l --full-time total 488 -rw-r--r-- 1 me mygroup 234329 2007-08-07 22:58:11.000000000 -0400 curl-7.15.5-2.el5.x86_64.rpm -rw-r--r-- 1 me mygroup 253488 2007-08-07 23:10:56.000000000 -0400 curl-7.16.4-1.fc8.x86_64.rpm ZB |
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08-08-2007
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I suppose, that is the precision in which the details are stored in the inode.
Even when you do a stat, HH : MM is the precision limit you get Code:
Access: 2007-05-12 01:54:00.000000000 Modify: 2007-05-12 01:54:00.000000000 Change: 2007-05-12 01:54:00.000000000  |
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08-08-2007
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ls -l --full-time is not working however. Is the precision configurable? I mean somewhere in the /etc ?
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08-08-2007
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a perl one-liner:
Code:
$ touch file.now $ perl -e '@d=localtime ((stat(shift))[9]); printf "%02d-%02d-%04d %02d:%02d:%02d\n", $d[3],$d[4]+1,$d[5]+1900,$d[2],$d[1],$d[0]' file.now 08-08-2007 10:20:36 $ |
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04-25-2009
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That perl one liner (below) works perfectly. Can someone please explain what it is actually doing? I actually need the timestamp in this format:
yyyymmddhhmmss perl -e '@d=localtime ((stat(shift))[9]); printf "%02d-%02d-%04d %02d:%02d:%02d\n", $d[3],$d[4]+1,$d[5]+1900,$d[2],$d[1],$d[0]' file.now 08-08-2007 10:20:36 I don't understand the significance of "08-08-2007 10:20:36" after the filename? |
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