How can I simplify the script

sudhish · #1 (**permalink**) 08-08-2007

Hi all,

How can I simplify following script,
Logic is to find two strings (strings are case sensitive) from a file.

if [ `grep -x "$1" "$path"/Hostname/$file_name|wc -l` -eq 1 ]; then
if [`grep -x "$2" "$path"/Hostname/$file_name|wc -l` -eq 1 ]; then
Group=`echo $1_hostname`
fi
fi

Please help me on this.

Regards
Sudhish s. kumar

lorcan · #2 (**permalink**) 08-08-2007

You can do something like

Code:

grep -x "$1" "$path"/Hostname/$file_name >/dev/null 2>&1
rtn1_val=$?
grep -x "$2" "$path"/Hostname/$file_name >/dev/null 2>&1
rtn2_val=$?

if [[ $rtn1_val -eq 0 && $rtn2_val -eq 0 ]]
then
        Group=`echo $1_hostname`
fi

bigearsbilly · #3 (**permalink**) 08-08-2007

grep -e "($1|$2)"

sudhish · #4 (**permalink**) 08-09-2007

Quote:

Originally Posted by bigearsbilly

grep -e "($1|$2)"

grep -e "(string1|string2)" /filename

This command is not working

In fact I was looking for some thing like you suggested

Thanks
Regards
Sudhish S. Kumar

lorcan · #5 (**permalink**) 08-09-2007

So are you trying to match either of the strings in your file, or do you want both of the strings to be present.

FOOGLE · #6 (**permalink**) 08-09-2007

try
/usr/xpg4/bin/grep -e 'string1|string2'

waiq · #7 (**permalink**) 08-09-2007

I think you need to escape the "|".. So grep -e "string1\|string2" filename should work.

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