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07-25-2007
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replacing a line of unknown charecters in a file
Hi All
I have a requirement where using a script I grep a file for string (KSG/Password in below ) , get the next line which is the password and I need replace the whole line of unknown special charecters (encrypted password) with another line as given below . As in below i need to get the line , assign it to a variable STRNG="<value>#!OE/+puLDjXm/Yg4W34vHvV6rdiGx0plE</value>" then replace $STRNG with "<value>psoft123</value>" The file i grep contains as below <value> </NameValuePair> <NameValuePairPassword> <name>KSG/Password</name> <value>#!OE/+puLDjXm/Yg4W34vLvV6rdiGx0plE</value> </NameValuePairPassword> <NameValuePair> <name>KSG/DB_User</name> <value>vass</value> </NameValuePair> when I use 'sed' as below , I get the error "sed:command garbled" sed 's/'$STRNG'/'<value>psoft123</value>'/' abc.xml > abc1.xml + sed s/ <value>#!OE/+puLDjXm/Yg4W34vHvV6rdiGx0plE</value>/<value>psoft123</value>/ abc.xml + 1> abc1.xml sed: command garbled: s/ Can some one please help me with this Thanks Malavm 
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07-25-2007
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Hi
Thanks for the reply but I am still getting the error bash-2.05$ sed '/KSG\/Password/{n;s#<value>.*</value>#<value>psoft123</value>;}' abc.xml sed: command garbled: /KSG\/Password/{n;s#<value>.*</value>#<value>psoft123</value>;}
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07-25-2007
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if you are open to alternative, here's a Python script:
Code:
#!/usr/bin/python
data=open("file").readlines()
data=[i.strip() for i in data]
for num,line in enumerate(data):
if "KSG/Password" in line:
data[num+1] = "<value>psoft123</value>"
for i in data:
print i
Code:
# ./test.py #or use > to redirect to new file <value> </NameValuePair> <NameValuePairPassword> <name>KSG/Password</name> <value>psoft123</value> </NameValuePairPassword> <NameValuePair> <name>KSG/DB_User</name> <value>vass</value> </NameValuePair>
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07-25-2007
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Quote:
Code:
sed '/KSG\/Password/{n;s#<value>.*</value>#<value>psoft123</value>#;}' abc.xml
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07-25-2007
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Code:
awk '{ if ( match($0, "KSG/Password") ) { getline; print "<value>psoft123<\/value>" } else { print } }' filename
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