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07-19-2007
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checking uid
How do i go about getting the uid of the user and verify ?
Code:
if [ $uid != 'root' ]
then
echo "You are not a superuser, please login as a superuser"
exit1;
fi
1. how to get the uid of the user ? i know by typing id but how to get the script to verify its a su? 2. how do i exit the whole script if he/she is not a su? 3. Is the above, able to continue the rest of the process if its a su? -Thanks & Regards- |
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07-19-2007
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use $USERNAME
Code:
if [ $USERNAME != 'root' ] then echo "you are not root" else echo "you are root" fi |
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07-19-2007
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hmmm ... i echo $USERNAME and i got nothing
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07-19-2007
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which shell and os are you using ?
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07-19-2007
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else you might try
Code:
id | sed 's/).*$//;s/^.*(//' |
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07-19-2007
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i'm using sun solaris 9, bash
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07-19-2007
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Quote:
Code:
$ ps -p $$
PID TTY TIME CMD
10387 pts/4 0:00 bash
$ id
uid=0(root) gid=1(other)
$ echo $UID
0
$ [ "$UID" -eq 0 ]||{ echo 'Go away!';exit 1;}
$ su - oracle
$ [ "$UID" -eq 0 ]||{ echo 'Go away!';exit 1;}
Go away!
logout
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