awk command to find the count of files ina directory

sish78 · #1 (**permalink**) 07-18-2007

hi Gurus,

can anyone provide a awk command to get teh count of number of file sin a specific directory.

appreciate any kind of information..

thanks

jjinno · #2 (**permalink**) 07-18-2007

This works but only if there actually are files in the directory... if there are only directories, or no files at all, it responds with an error and a '-1', because the 'ls -l' fails

Code:

ls -l *.* | wc | awk -F ' ' '{print $1-1}'

matrixmadhan · #3 (**permalink**) 07-19-2007

Code:

ls -1  |awk 'END{print NR}'

aajan · #4 (**permalink**) 07-19-2007

ls -l |grep '^-' | wc-l

matrixmadhan · #5 (**permalink**) 07-19-2007

Quote:

Originally Posted by aajan

ls -l |grep '^-' | wc-l

OP had asked a solution with awk

moreover the above could be modified as just

Code:

ls -1 | wc -l

aajan · #6 (**permalink**) 07-19-2007

By doing so, it wil count the directories also my dear pal

ghostdog74 · #7 (**permalink**) 07-19-2007

Quote:

Originally Posted by sish78

hi Gurus,

can anyone provide a awk command to get teh count of number of file sin a specific directory.

appreciate any kind of information..

thanks

awk script for a specific directory (ie. a directory you specify) :

Code:

awk 'BEGIN {
	while ( ( "ls -l /yourdir" | getline line ) >0 ) {
		if ( line ~ /^-/ ){
			c++
		}
	}
	print "Total files: ", c
     }
'

or simply (for a specific directory):

Code:

ls -ltr | awk '/^-/{ c++;}END{print c}'

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