another perl question

hankooknara · #1 (**permalink**) 07-07-2007

I fail to see how below answer is 1? can someone explain this for me?

DB<3> $string = "The cat sat on the mat";

DB<4> $animal = ($string =~ m/The (.*) sat/);

DB<5> print $animal;
1

cbkihong · #2 (**permalink**) 07-07-2007

This behaviour is explained in the perlop manpage for m// binding in scalar context:

http://www.annocpan.org/~NWCLARK/per...perlop.pod#256

Quote:

Searches a string for a pattern match, and in scalar context returns true if it succeeds, false if it fails. If no string is specified via the =~ or !~ operator, the $_ string is searched. (The string specified with =~ need not be an lvalue--it may be the result of an expression evaluation, but remember the =~ binds rather tightly.) See also perlre. See perllocale for discussion of additional considerations that apply when use locale is in effect.

hankooknara · #3 (**permalink**) 07-07-2007

thank you...

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