Hi all,

i was doing a small program where if i was to be given the first 3 letters of any month i.e. in the form of Jan or Apr then it would return the column number where it finds a match. To do this i created a 12 element array of months with first 3 letters and if i echo'ed the contents of the array, piped it into another command that would return me a column number where it matched. i thought awk could do this by replacing 'print' with 'find' but it doesn't work although it doesn't give an error message. Is there a command already out there that does this?

thanks

Mani

Mani,

Can you post your problem ?

that would help us to give currect solution.

I suppose you want to scan a file, and then find the file's line which contain Abbrevision for MONTH, and then print the line's line number.

Follow maybe can help u, just for you reference:

The file content(a.txt):

this is Mar
now come a Feb
then another Mar
he a Jun comes

read mon
echo "The line number which contain ${mon} is as follow:"
sed "/$mon/=" a.txt