How to find the first day of previous month in unix?

mohapatra · #1 (**permalink**) 06-28-2007

How to find the first day of previous month in unix mmddyyyy format?

example : today is 07052007 (in mmddyyyy)
output sud be 06012007

thanks
mohapatra

vgersh99 · #2 (**permalink**) 06-28-2007

... by examining the FAQ section first and by experimenting.

#3 (**permalink**) 06-28-2007

This should get you closer. Try to check for day=1

Code:

THIS_MONTH=`date +%m`
THIS_YEAR=`date +%Y`
 
LAST_MONTH=`expr $THIS_MONTH - 1`
if [ $LAST_MONTH = 0 ]
  then
    LAST_MONTH=12
    THIS_YEAR=`expr $THIS_YEAR - 1`
fi
 
cal $LAST_MONTH $THIS_YEAR | head -3 | tail -2

Perderabo · #4 (**permalink**) 06-28-2007

Code:

$ set -A lastmo $(datecalc -a $(date "+%Y %m") 1 - 1)
$ lastmo[2]=1
$ printf "%04d%02d%02d\n" ${lastmo[*]}
20070501
$

mohapatra · #5 (**permalink**) 07-02-2007

In te above example , what is datecalc ?

jim mcnamara · #6 (**permalink**) 07-02-2007

The datecalc script perderabo put in the FAQ section - the one section we keep asking you to read.

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