Hi

i have part of the scripts below ,getopt for -h or ? not working for me.
can anybody tell me if this sytax right or wrong.

#!/usr/bin/ksh
program=$(basename $0)
#####################################################################################
function usageerr
{
RC=1
USAGE="$program -s PROD_SCHEMA_NAME -d DEST_SCHEMA_NAME "
echo " usage:\n $USAGE "
exit $RC
}
######################################################################################
while getopts s:d:h arguments
do
case $arguments in
s|S) SRCE_SCHEMA_NAME=$OPTARG;;
d|D) DEST_SCHEMA_NAME=$OPTARG ;;
h|H|?) usageerr ;;
*) echo " $program :$OPTARG requires a value." ;;
esac
done
shift $(($OPTIND -1))
if [[ $# -le 1 ]]
then
echo " Incorrect number of arguments "
usageerr
fi

Thanks u

Grepme,
You cannot use question mark "?" -- nor colon ":" -- as option characters.

Hi thanks for your reply Sir,

I have checked the man it says you can use the ? mark .


Thanks

From man page of "getopts" on SunOS: