manipulate a passed in parameter - Shell Programming and Scripting

rudoraj · #1 (**permalink**) 06-11-2007

I am passing a file name as a parameter to shell script
the parameter is getfile.txt.gpg

how do i process this parameter to get name like getfile.txt only and eleminate the .gpg text??

Thanks in advance

jim mcnamara · #2 (**permalink**) 06-11-2007

Try:

Code:

#!/bin/ksh
file="$1"
workfile=${file%*.gpg}
echo "$workfile"

rudoraj · #3 (**permalink**) 06-11-2007

works fine
Thank you

I tried the following and works fine too

x=`echo $1|wc -c`
y=`expr $x - 5`
z=`echo $1|cut -c1-$y`
echo $z

Thank you

can you explain your code please??

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