Checking numeric value

malaymaru · #1 (**permalink**) 05-25-2007

Hi,

How can I check numeric value in shell?

I am passing one parameter (integer) and I want to restrict any other characters except 0-9.

./script xyz 10

Here 2nd parameter (10) should be integer only.

Can anyone help on this?

Malay

funksen · #2 (**permalink**) 05-25-2007

Code:

if [[ ! -z $(echo $2 | sed 's/[0-9]//g') ]]
then
echo "integer only"; exit
fi

should work

ghostdog74 · #3 (**permalink**) 05-25-2007

Code:

#echo "1234"  | awk '/^[0-9]+$/' 
1234
#echo "12sasd34"  | awk '/^[0-9]+$/'
#

Abhishek Ghose · #4 (**permalink**) 05-25-2007

Here's an oneliner:

awk -v x=$a 'END{if(x==x+0) print "integer"}' /dev/null

In this example , a is shell variable.
If a=10, then the output of above is "integer"
If a="10abhishek", then the output of above is ""

mahesh. · #5 (**permalink**) 05-25-2007

I want get system open file table value , Can u help.

Thanking you,
Mahesh

aigles · #6 (**permalink**) 05-25-2007

With bash (extglob option must be on) and ksh :

Code:

if [[ "$var" != +([0-9]) ]]
then
   echo "Not an Integer"
fi

Jean-Pierre.

cfajohnson · #7 (**permalink**) 05-25-2007

Quote:

Originally Posted by malaymaru

How can I check numeric value in shell?

I am passing one parameter (integer) and I want to restrict any other characters except 0-9.

./script xyz 10

Here 2nd parameter (10) should be integer only.

Code:

case $2 in
  *[^0-9]*) echo not integer; exit 1 ;;
esac

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