Count the number of occurence of perticular word from file

rinku · #1 (**permalink**) 05-25-2007

I want to count the number of occurence of perticular word from one text file.

Please tell me "less" command is work in ksh or not. If it is not working then instead of that which command will work.

blowtorch · #2 (**permalink**) 05-25-2007

The 'less' command is used to view a file. Use grep to search for a particular word in a file. You can use this to count the number of occurrences too, just check the man page for the exact switch.

funksen · #3 (**permalink**) 05-25-2007

grep -o <string> <file> | wc -w

cfajohnson · #4 (**permalink**) 05-25-2007

Quote:

Originally Posted by rinku

I want to count the number of occurence of perticular word from one text file.

Code:

tr -cs 'A-Za-z' '\n' < FILE | grep -c "WORD"

pelipeplips · #5 (**permalink**) 08-08-2007

Quote:

grep -o <string> <file> | wc -w

I tried using grep with the "-o" option and it gives me this error:
grep: illegal option -- o
What does "-o" option do?

I also need to find an occurence of a certain string within a file. Currently I'm using:

Code:

grep -c 'abc' sample.txt

Klashxx · #6 (**permalink**) 08-08-2007

Use:

Code:

awk '{ 
     for (i=1;i<=NF;i++)
         if ( $i == "abc")
         c++
     }
END{
print c}' sample.txt

matrixmadhan · #7 (**permalink**) 08-08-2007

Quote:

Originally Posted by Klashxx

Code:

awk '
BEGIN {
RS=FS
}
{
if ( $0 ~ /abc/ )
   c++
}
END{
print c++
}' lsample.txt

there is one more problem with that

with the input posted by Shell and for search pattern as "aa" it would match "aaa" also

try this,

Code:

awk ' BEGIN {RS=FS} { if ( $0 ~ /^aa$/ ) { c++; i=NR; } } END{if ( i == NR ) { c++ } print c}' filename

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