Count the number of occurence of perticular word from file - Page 3

cfajohnson · #1 (**permalink**) 08-09-2007

Quote:

Originally Posted by Shell_Life

Using the same test data:

Code:

a aa aaa
aaa aa a
aaa aa a aaa aa a aaa

This solution does not work for the following case:

Code:

tr -s ' \011\012' '\n\n\n' < FILE | grep -c "a"

It gives the total of words as '13', when the answer is '4'.

Then you need to adjust your grep to search for a word, not a letter. If your grep has it, use -w; if not, use "\<a\>".

Also, some older versions of tr need \012 instead of \n.

ghostdog74 · #2 (**permalink**) 08-08-2007

Quote:

Originally Posted by rinku

I want to count the number of occurence of perticular word from one text file.

Please tell me "less" command is work in ksh or not. If it is not working then instead of that which command will work.

See here for example

namishtiwari · #3 (**permalink**) 08-10-2007

Here is the command which you can use-

grep -o "string" filename | wc -w

fazliturk · #4 (**permalink**) 08-10-2007

try this
count1=`wc -w inputfile`
count2=`sed s/word/" "/g inputfile |wc -w`

/*number of word =count1-count2*/

kahuna · #5 (**permalink**) 08-10-2007

Quote:

Originally Posted by fazliturk

count1=`wc -w inputfile`
count2=`sed s/word/" "/g inputfile |wc -w`

/*number of word =count1-count2*/

I don't think this works if the word is in the middle of a larger word.

Code:

$echo compoundwordinmiddle >inputfile      
$count1=`wc -w inputfile`                  
$count2=`sed s/word/" "/g inputfile |wc -w`
$echo $count1
1 inputfile
$echo $count2
2

fazliturk · #6 (**permalink**) 08-10-2007

Quote:

Originally Posted by kahuna

I don't think this works if the word is in the middle of a larger word.

Code:

$echo compoundwordinmiddle >inputfile      
$count1=`wc -w inputfile`                  
$count2=`sed s/word/" "/g inputfile |wc -w`
$echo $count1
1 inputfile
$echo $count2
2

yes you are right but if not this code is very simple

kahuna · #7 (**permalink**) 08-10-2007

Quote:

Originally Posted by fazliturk

yes you are right but if not this code is very simple

"echo 1" is very simple, but also not correct

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