regular expression across some lines

ynixon · #1 (**permalink**) 05-24-2007

I am trying to use regular expression to identify ONLY the commands that hasn't the word "tablespace" within it. a command starts with "create table" and ends with ; (semicolon)

example file:

Code:

create table first tablespace ;
create table second
(
  BBL_CUSTOMER_NAME      VARCHAR2(32),
a tablespace af
);
create table third
(
  BBL_CUSTOMER_NAME      VARCHAR2(32),
);
create table 
forth
(
  BBL_CUSTOMER_NAME      VARCHAR2(32) );

the match should be:

Code:

create table third
(
  BBL_CUSTOMER_NAME      VARCHAR2(32),
);
create table 
forth
(
  BBL_CUSTOMER_NAME      VARCHAR2(32) );

HELP ME

aigles · #2 (**permalink**) 05-24-2007

You can try something like that :

Code:

awk '
   BEGIN { 
      RS=ORS=";\n"
   }
   /create/ && ! /tablespace/ {
      sub(/^\n*/, "");
      print
   }
    ' inputfile

Jean-Pierre.

anbu23 · #3 (**permalink**) 05-24-2007

Code:

awk -v RS=";\n" -v ORS=";\n" ' !/tablespace/ ' filename

ynixon · #4 (**permalink**) 05-24-2007

I'd like to try using only grep

drl · #5 (**permalink**) 05-24-2007

Hi.

I think that grep will not cross newlines, so that you would need to place your commands each on a single line. There is a note in my man grep page about using perl regular expressions, but that it is undocumented. The awk and perl scripts can make use of settable record boundaries.

Here's a perl quickie:

Code:

#!/bin/sh

# @(#) s1       Demonstrate perl quickie for unmatched string across lines.

FILE=${1-data1}

perl -wn -e 'BEGIN{$/=";"} print if not /tablespace/' $FILE

exit 0

And running this on your sample contained in file data1:

Code:

% ./s1

create table third
(
  BBL_CUSTOMER_NAME      VARCHAR2(32),
);
create table
forth
(
  BBL_CUSTOMER_NAME      VARCHAR2(32) );

Best wishes ... cheers, drl

ynixon · #6 (**permalink**) 05-24-2007

Quote:

Originally Posted by drl

Hi.

I think that grep will not cross newlines, so that you would need to place your commands each on a single line. There is a note in my man grep page about using perl regular expressions, but that it is undocumented. The awk and perl scripts can make use of settable record boundaries.

Here's a perl quickie:

Code:

#!/bin/sh

# @(#) s1       Demonstrate perl quickie for unmatched string across lines.

FILE=${1-data1}

perl -wn -e 'BEGIN{$/=";"} print if not /tablespace/' $FILE

exit 0

And running this on your sample contained in file data1:

Code:

% ./s1

create table third
(
  BBL_CUSTOMER_NAME      VARCHAR2(32),
);
create table
forth
(
  BBL_CUSTOMER_NAME      VARCHAR2(32) );

Best wishes ... cheers, drl

clean and simple

vgersh99 · #7 (**permalink**) 05-24-2007

Quote:

Originally Posted by ynixon

I'd like to try using only grep

why is that?

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