![]() |
Hello and Welcome from United States to the UNIX and Linux Forums! Thank You for Visiting and Joining Our Global Community.
|
|
google unix.com
|
|||||||
| Forums | Register | Forum Rules | Links | Albums | FAQ | Members List | Calendar | Search | Today's Posts | Mark Forums Read |
| Shell Programming and Scripting Post questions about KSH, CSH, SH, BASH, PERL, PHP, SED, AWK and OTHER shell scripts and shell scripting languages here. |
More UNIX and Linux Forum Topics You Might Find Helpful
|
||||
| Thread | Thread Starter | Forum | Replies | Last Post |
| Code Understand ? | varungupta | UNIX for Advanced & Expert Users | 2 | 05-02-2008 07:34 PM |
| Can't understand sar command | shaan_dmp | UNIX for Dummies Questions & Answers | 1 | 10-23-2007 07:04 AM |
| can't understand this at all. | severndigital | UNIX for Dummies Questions & Answers | 4 | 02-21-2007 12:21 PM |
| can't understand | BoyArcher | UNIX for Dummies Questions & Answers | 5 | 03-14-2006 09:36 AM |
|
|
LinkBack | Thread Tools | Search this Thread | Rate Thread | Display Modes |
|
||||
|
Want to understand the meaning of the following line
HI All
Please find the code below from a script called test.sh echo "Hello World" . test_common.lib get_info in the file test_common.lib i have the following contents get_info() { c_cnt=0; cm=""; echo "Inside get_info" } when i run the script test.sh i get a error message test.sh: line 3: get_info: command not found First of all i would like to know how this line behaves "test_common.lib" Regards Dhanamurthy |
| Bookmarks |
| Thread Tools | Search this Thread |
| Display Modes | Rate This Thread |
|
|