regexp to print after a field seperator

ramky79 · #1 (**permalink**) 05-08-2007

Hi,
How do i Print anything after a ':'

Ex :
file1: 1235131(rs32553)

I want to print out "1235131(rs32553)"
how do i do it. I know we can do this using awk but looking for the right syntax.

Any help appreciated.

Thanks,
Ram

vgersh99 · #2 (**permalink**) 05-08-2007

Code:

echo 'file1: 1235131(rs32553)' | sed 's/.*:\(.*\)/\1/'

jim mcnamara · #3 (**permalink**) 05-08-2007

Code:

echo "file1: 1235131(rs32553)" | sed 's/^.*://'

sed works, too.

aigles · #4 (**permalink**) 05-08-2007

Another way with cut :

Code:

echo "file1: 1235131(rs32553)" | cut -d: -f2-

Jean-Pierre.

anbu23 · #5 (**permalink**) 05-09-2007

Code:

echo "file1: 1235131(rs32553)" | awk ' sub("[^:]*:","") '

jim mcnamara · #6 (**permalink**) 05-09-2007

Code:

echo "file1: 1235131(rs32553)" |awk -F: '{print $2}'

radoulov · #7 (**permalink**) 05-09-2007

Code:

$ echo "file1: 1235131(rs32553)"|{ read; echo "${REPLY#*: }";}
1235131(rs32553)

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