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  #1 (permalink)  
Old 04-29-2007
unics unics is offline
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Join Date: Apr 2007
Posts: 7
sort help
Before
2007-04-29 01:02:02.440
2007-04-28 01:02:02.446
2007-04-29 01:02:15.113
2007-05-29 01:02:15.113
2007-04-28 09:09:04.939
2007-04-29 09:09:04.952
2007-05-29 09:09:05.886
2007-04-29 09:09:05.887
2007-04-28 09:00:49.066

After
2007-04-28 01:02:02.446
2007-04-28 09:00:49.066
2007-04-28 09:09:04.939
2007-04-29 01:02:15.113
2007-04-29 09:09:03.965
2007-04-29 09:09:04.952
2007-05-29 01:02:15.113
2007-05-29 09:09:05.886


How do i sort this in ascending order of year month date and for each date the timestamps should be in ascending order...
  #2 (permalink)  
Old 04-29-2007
jim mcnamara jim mcnamara is offline Forum Staff  
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Join Date: Feb 2004
Location: NM
Posts: 5,717
Code:
tr -s ':' ' ' < filename | tr -s '-' ' ' | sort | \
awk '{ printf("%s-%s-%s %s:%s:%s\n", $1, $2, $3, $4, $5, $6) }'
output
Code:
2007-04-28 01:02:02.446
2007-04-28 09:00:49.066
2007-04-28 09:09:04.939
2007-04-29 01:02:02.440
2007-04-29 01:02:15.113
2007-04-29 09:09:04.952
2007-04-29 09:09:05.887
2007-05-29 01:02:15.113
2007-05-29 09:09:05.886
  #3 (permalink)  
Old 04-29-2007
drl's Avatar
drl drl is offline Forum Advisor  
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Join Date: Apr 2007
Location: Saint Paul, MN USA / BSD, CentOS, Debian, OS X, Solaris
Posts: 704
Hi.

The before and after files are different in length.

Because you have the columns so nicely lined up, you should be able to use sort with just a few keys:
Code:
#!/bin/sh

# @(#) s1       Demonstrate sort for date and time.

# sample:
# 2007-04-29 01:02:02.440
# Everything is in columns, so just sort on key 1 and then key 2.

sort -k1,2 -k2 data1 |
tee data2

if ! cmp data2 results.txt
then
        echo
        echo " Results from diff:"
        echo
        diff -y -W72 --suppress-common-lines data2 results.txt
else
        echo
        echo " Files are identical."
fi

exit 1
Producing:
Code:
% ./s1
2007-04-28 01:02:02.446
2007-04-28 09:00:49.066
2007-04-28 09:09:04.939
2007-04-29 01:02:02.440
2007-04-29 01:02:15.113
2007-04-29 09:09:04.952
2007-04-29 09:09:05.887
2007-05-29 01:02:15.113
2007-05-29 09:09:05.886

 Files are identical.
where the file results.txt is from jim's post, data1 is your input data, and data2 is the sort output ... cheers, drl
  #4 (permalink)  
Old 04-29-2007
unics unics is offline
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Join Date: Apr 2007
Posts: 7
thx
Before
qa,2007-04-29 01:02:02.440
df,2007-04-28 01:02:02.446
gf,2007-04-29 01:02:15.113
df,2007-05-29 01:02:15.113
jh,2007-04-28 09:09:04.939
lk,2007-04-29 09:09:04.952
uj,2007-05-29 09:09:05.886
ki,2007-04-29 09:09:05.887
gy,2007-04-28 09:00:49.066

After
df,2007-04-28 01:02:02.446
gy,2007-04-28 09:00:49.066
jh,2007-04-28 09:09:04.939
qa,2007-04-29 01:02:02.440
gf,2007-04-29 01:02:15.113
lk,2007-04-29 09:09:04.952
ki,2007-04-29 09:09:05.887
df,2007-05-29 01:02:15.113
uj,2007-05-29 09:09:05.886

If the data is in the above format how can we sort?
  #5 (permalink)  
Old 04-29-2007
drl's Avatar
drl drl is offline Forum Advisor  
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Join Date: Apr 2007
Location: Saint Paul, MN USA / BSD, CentOS, Debian, OS X, Solaris
Posts: 704
Hi, unics.

You've seen two solutions to a similar problem.

How would you go about analyzing this problem after consulting man pages?

What commands and options would you use?

Show us some of your attempts and work ... cheers, drl
  #6 (permalink)  
Old 04-29-2007
unics unics is offline
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Join Date: Apr 2007
Posts: 7
Hi
I have tried

sort -t"," -k2.1,2.4n -k2.6,2.7n -k2.9,2.10n -k2.12,2.13n -k2.15,2.16n -k2.18,2.19n -k2.21,2.23n

but somehow seems to work sometimes..dont know whats the prob..anything that needs to be corrected?
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