variable inside awk '{print $c}'

Tártaro · #1 (**permalink**) 04-13-2007

i'm trying to do this (in bash darwin);

echo "give me some words: "
read a
c=2 # this is get by other ways
echo $a | awk '{print $c}' # i want to print the column given
# by de $c variable

if there is someone understand what i pretend and see what im doing wrong, please help me.thanks

anbu23 · #2 (**permalink**) 04-13-2007

Code:

echo $a | awk -v c=$c '{print $c}'

or

Code:

echo $a | awk '{print $'$c'}'

Tártaro · #3 (**permalink**) 04-13-2007

thank you man.it works perfectly.

radoulov · #4 (**permalink**) 04-13-2007

Code:

awk 'BEGIN { print "Give me some words (Ctrl+C to exit):" }
{ print $c; next }' c=2

More UNIX and Linux Forum Topics You Might Find Helpful
Thread	Thread Starter	Forum	Replies	Last Post
getting variable inside awk	subin_bala	Shell Programming and Scripting	1	06-05-2008 04:21 AM
Using a variable inside a file to cat another.	MaestroRage	UNIX for Dummies Questions & Answers	3	02-06-2008 02:17 PM
passing a variable inside a variable to a function	KingVikram	UNIX for Dummies Questions & Answers	2	01-14-2008 08:28 PM
How to replace variable inside the variable	mani_um	Shell Programming and Scripting	31	08-09-2007 10:56 PM
ksh: A part of variable A's name is inside of variable B, how to update A?	pa3be	Shell Programming and Scripting	4	03-30-2005 11:29 AM

Thread Tools	Search this Thread
Show Printable Version Email this Page	Search this Thread: Advanced Search
Display Modes	Rate This Thread
Switch to Linear Mode Hybrid Mode Switch to Threaded Mode	Rate This Thread:


	Powered by