how to print backslah using echo

mani_um · #1 (**permalink**) 04-12-2007

how to print 3 backslah using Unix AIX,
i have try in my fedora and AIX,both give dirrent output for same echo statment
test.sh

Code:

sed -e 's/\(["`]\)/\\\1/g' -e 's/\$?/\\$?/g' -e 's/\$#/\\$#/g' -e 's/^/echo "/g' -e 's/$/ "/g' xMNBDF070 > xMNBDF070_test

xMNBDF070

Code:

sed -e "s/'/\\\'/g" -e 's/\([();*|>]\)/\\\1/g' $SCRIPTSQL/xMNBDF070_Script.sql > $TEMP_PATH/xMNBDF070_Script.sql.TMP

letsay,
SCRIPTSQL=/home/mani
TEMP_PATH=/home/mani/temp

sh xMNBDF070_test
output

Code:

sed -e "s/'/\\\'/g" -e 's/\([();*|>]\)/\\\1/g' /home/mani/xMNBDF070_Script.sql > /home/mani/temp/xMNBDF070_Script.sql.TMP

how to alter test.sh to print above line in xMNBDF070
because i get this

Code:

sed -e "s/'/\'/g" -e 's/\([();*|>]\)/\1/g' /home/mani/xMNBDF070_Script.sql > /home/mani/temp/xMNBDF070_Script.sql.TMP

i dunno how many backslah to use because in Unix to get 3 backslah i echo like this
echo "\\\\\\\\\ "

but in linux i use pair backslah
echo "\\\\\\ "

why its diffrent and how to know how many backslach needed
please guide

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