hello,

I have the following script to check the invoice number is in order or not.
However, it cannot show out the correct information. My expect output show below and I would like to only list out the NOT IN SEQUENCE inovice number (not included "ok")

#!/bin/sh
start=1
for file_number in `ls -1 /appl/appl/archive/client/CACHE/CLIENTINVOICE*[0-9].archived | sort | cut -c 48,49,50,51`
do
if [ $start -eq 1 ] ; then
# this is the first pass of the loop, so we've got nothing to compare
start=0
previous=$file_number
else
# this is not the first pass of the loop
previous=`expr $previous + 1`
echo "comparing $file_number and $previous ... "
if [ $file_number = $previous ] ; then
echo "OK"
else
seqno=`expr $file_number - 1`
echo "CLIENTINVOICE$invoiceno are not in sequence "
fi
fi
previous=$file_number
done


input:
01185
01191
01192
01193
01196
01197
.
.
.

script output:
01190 are not in seq
01195 are not in seq

expect output
01186 are not in seq
01187 are not in seq
01188 are not in seq
01189 are not in seq
01190 are not in seq
01194 are not in seq
01195 are not in seq