exit a shell script!!

sami98 · #1 (**permalink**) 03-27-2007

could somebody tell me please how to exit a shell script:

if [ $# -eq 0 ]
then
echo "No arguments detected"
exit 1
fi
...
echo "still there" # is displayed .. :-(

anbu23 · #2 (**permalink**) 03-27-2007

Code:

if [ $# -eq 0 ]
then
echo "No arguments detected"
exit 1 #exit shell script  
fi
...
echo "still there" # is displayed .. :-(

sami98 · #3 (**permalink**) 03-27-2007

sorry...... I have the following situation and it does not work :-( :

if [ $# -eq 0 ]
then
usage()
fi

echo "still there.."

usage {
echo "No arguments detected"
exit 1 #exit shell script
}

dennis.jacob · #4 (**permalink**) 03-27-2007

Try this..

Code:

function  usage {
echo "No arguments detected"
exit 1 #exit shell script
}
if [ $# -eq 0 ]
then
usage
fi

echo "still there.."

Dhruva · #5 (**permalink**) 03-27-2007

Function must be declared before it is used in script.try the below script..

Code:

usage ()
{
echo "No arguments detected"
exit 1 #exit shell script
}

if [ $# -eq 0 ];
then
usage
fi

echo "still there.."

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