yet another awk field syntax question

prkfriryce · #1 (**permalink**) 03-22-2007

I am trying to print the remaing fields and field numbers beginning with a field 'xyz'

Code:

#cat abc
test1:test2:xyz:test3:test4:test5

#cat def
test1:test2:test3:xyz:test4:test5

desired output is to be able to print NF and any trailing fields separated by':'

test3 3
or
test4 3
or
test5 3

likewise,

test4 2
or
test5 2

placeing a field separator as 'xyz' illiminates using ':' as a second separator or is that possible?

anbu23 · #2 (**permalink**) 03-22-2007

Code:

awk -F: -v OFS="\nor\n" ' { sub(".*xyz:",""); for(i=1;i<=NF;++i) $i=$i" "NF ;print }  ' file

prkfriryce · #3 (**permalink**) 03-22-2007

I'm gonna use sed for the time being, but would like to know the correct awk syntax as well

cat abc | sed 's/$.*$xyz://' | awk -F: '{print $1,NF}'

edit*

Quote:

Originally Posted by anbu23

Code:

awk -F: -v OFS="\nor\n" ' { sub(".*xyz:",""); for(i=1;i<=NF;++i) $i=$i" "NF ;print }  ' file

thanks, i'll try it

anbu23 · #4 (**permalink**) 03-22-2007

Quote:

Originally Posted by prkfriryce

I'm gonna use sed for the time being, but would like to know the correct awk syntax as well

cat abc | sed 's/$.*$xyz://' | awk -F: '{print $1,NF}'

edit*

thanks, i'll try it

You can do everything in awk.Check my previous post

prkfriryce · #5 (**permalink**) 03-22-2007

Quote:

Originally Posted by anbu23

You can do everything in awk.Check my previous post

yeah works well, a little too well! i was looking for a more simplified version by printing the fields individually, but the 'sub' syntax is what i was looking for. I'll tweek it for future applications.

thanks again

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