checking size of the first line in a log file - Shell Programming and Scripting

kiran1112 · #1 (**permalink**) 03-21-2007

Hi My test.log file looks like this:

Code:

   0 190_GSTV_HUX_003QISCGSK026_error070322_115331917.log
   34 190_GSTV_HUX_003QISCGSK026_error070117_151311385.log
   12 190_GSTV_HUX_003QISCGSK026_error070117_151230001.log
   2 190_GSTV_HUX_003QISCGSK026_error070117_101010001.log
   0 190_GSTV_HUX_003QISCGSK026_error070117_0832001254.log
   0 190_GSTV_HUX_003QISCGSK026_error070115_122813125.log
   3 190_GSTV_HUX_003QISCGSK026_error070115_115331917.log
   0 190_GSTV_HUX_003QISCGSK026_error070115_114442254.log
   0 190_GSTV_HUX_003QISCGSK026_error070112_1156001509.log

Now i need to write a script which checks for the size of the first log file
ie.,in this case the size of "190_GSTV_HUX_003QISCGSK026_error070322_115331917.log"
please note that the test.log will be updated everytime i run a script and only the part remains constant is '190_GSTV_HUX_003QISCGSK026_errorXXXXXX_XXXXXXXXX.log'

is there any cmd which checks for the size of the first line in the test.log file and give the result?using which i need to write a condition...

Presently i tried this:

Code:

check=`cat /home/user/test.log | awk '{print $1}'`

but it is giving the output as :
0 34 12 2 0 0 3 0 0

if i use the condition

Code:

if [ $check = 0 ]

i m getting error as "A test command parameter is not valid."
beacause check contains 0 32 12 2 .......

Please can some one help me in this regard???
Thanks in advance

dennis.jacob · #2 (**permalink**) 03-21-2007

Give a try on this..

Quote:

awk -F" " 'NR==1 {print $1}' filename

Thnx.Dennis

matrixmadhan · #3 (**permalink**) 03-22-2007

Quote:

is there any cmd which checks for the size of the first line in the test.log file and give the result?using which i need to write a condition...

Code:

awk -F " " '{ print length($2) }' filename

dennis.jacob · #4 (**permalink**) 03-22-2007

Quote:

Originally Posted by matrixmadhan

Code:

awk -F " " '{ print length($2) }' filename

Hi Matrix,

Seems like this thread is a continuation of the below thread...I think he is not looking for the size of the second field.....rather, the first field which is the size of the file..

script to check for a condition inside a file

matrixmadhan · #5 (**permalink**) 03-22-2007

how about this,

Code:

ls -l `awk -F" " 'NR == 1 { print $2; exit }' file` | awk '{ print 5 }'

vino · #6 (**permalink**) 03-22-2007

Code:

sed -n -e "s/^ *\([^ ]*\) *.*_error.*/\1/p;q" /home/user/temp.log

kiran1112 · #7 (**permalink**) 03-22-2007

Hi all
many thanks for all your suggestions
but none of the commands is able to give the size of only the first line.
the following cmds

Code:

awk -F" " 'NR=1{print $1}' test.log
and 
sed -n -e "s/^ *\([^ ]*\) *.*_error.*/\1/p;"  test.log
and
 ls -l `awk -F" " 'NR == 1 { print $2; exit }' test.log` | awk '{ print 1 }'

gives the first column for all the files...but i only need for the first one

any help is appreciated
Thanks
Kiran

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