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03-06-2007
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String parse question
I have a string of data that looks like this:
[1] private.enterprises.954.1.1.1.1.1.2618 \(OctetString\): U [2] private.enterprises.954.1.1.1.1.2.2618 \(OctetString\): 2618 I am trying to parse the string to only return the values after the ":". Ex from above "U" and "2618". Any suggestions? 
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03-06-2007
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One way:
Code:
$ cat string
#! /usr/bin/ksh
string="[1] private.enterprises.954.1.1.1.1.1.2618 \(OctetString\): U [2] private.enterprises.954.1.1.1.1.2.2618 \(OctetString\): 2618"
echo string = $string
string=${string#*: }
first=${string%% *}
second=${string##*: }
echo first = $first
echo second = $second
exit 0
$ ./string
string = [1] private.enterprises.954.1.1.1.1.1.2618 \(OctetString\): U [2] private.enterprises.954.1.1.1.1.2.2618 \(OctetString\): 2618
first = U
second = 2618
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03-06-2007
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Quote:
Code:
var="abc:def ghi jkj:lmn opq"
left1=${var%%:*} ## Everything to the left of the first colon
left2=${var%:*} ## Everything to the left of the rightmost colon
right1=${var##* } ## Everything to the right of the rightmost space
right2=${var#* } ## Everything to the right of the first space
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03-06-2007
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Assuming that the variable var contains the above data
echo $var | awk -F: '{print substr($2,1,2)" " $3;}'
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03-06-2007
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Code:
echo "[1] private.enterprises.954.1.1.1.1.1.2618 \(OctetString\): U [2] private.enterprises.954.1.1.1.1.2.2618 \(OctetString\): 2618" | sed 's/\(.*\): \(.*\) \[\(.*\): \(.*\)/\2\ \4/'
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