How to include a variable between apostrophes within a command - Shell Programming and Scripting

guarriman · #1 (**permalink**) 02-21-2007

Hi.

I'm trying to find some words within my directory and created a text file containing them which is read by my shell script:

Code:

#!/bin/bash
var=`cat words.txt`
for i in $var; do
	echo $i
        find -type f -print0 | xargs -r0 grep -F '$i'
done

But it searches "$i" (dollar sign with 'i'), and not the word. How to do it?

Thank you very much.

vino · #2 (**permalink**) 02-21-2007

Quote:

Originally Posted by guarriman

Code:

#!/bin/bash
var=`cat words.txt`
for i in $var; do
	echo $i
        find -type f -print0 | xargs -r0 grep -F '$i'
done

Code:

find -type f -print0 | xargs -r0 grep -F "$i"

Shell_Life · #3 (**permalink**) 03-16-2007

guarriman,
You can try:
ls -1 | egrep -f words.txt

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