Set the 'DISPLAY' environment variable script

orno · #1 (**permalink**) 02-12-2007

Hello once again

Im trying to set my DISPLAY variable using a script, so i wrote the following:

Code:

#!/bin/sh
HOME=10.100.1.100
OFFICE1=10.100.1.101
OFFICE2=10.100.1.102

for TEST in HOME OFFICE1 OFFICE2
do
  if [ $1 = $TEST ]
      then
      export DISPLAY=${$TEST}
      break
  else
      echo "Not Matched"
  fi
done

I expect to use this script to say something like: setdisplay HOME and then it sets my DISPLAY variable to 10.100.1.100, so when I launch some X processes, it displays on my computer at home

There is obviously something wrong with the way I'm implementing the $($...)) part, except I don't know what. Is there any proper way to do this?

Also, if someone has any recommendations on how to implement what I want in a more efficient way, by all means, enlighten me

Thanks!

tayyabq8 · #2 (**permalink**) 02-12-2007

Try this:

Code:

#!/bin/sh
case $1 in
HOME)      export DISPLAY=10.100.1.100
;;
OFFICE1)   export DISPLAY=10.100.1.101
;;
OFFICE2)   export DISPLAY=10.100.1.102
;;
*)         echo "Not Matched"
esac

In your script, yeah value assignment was wrong, you can try export DISPLAY=${TEST} or export DISPLAY=$TEST

Regards,
Tayyab

anbu23 · #3 (**permalink**) 02-12-2007

try this

Code:

#!/bin/sh
HOME=10.100.1.100
OFFICE1=10.100.1.101
OFFICE2=10.100.1.102

for TEST in \$HOME \$OFFICE1 \$OFFICE2
do
  if [ $1 = $TEST ]
      then
      export DISPLAY=$(eval echo $TEST)
      break
  else
      echo "Not Matched"
  fi
done

orno · #4 (**permalink**) 02-12-2007

aha
great

so thats how u use eval

thanks for the help guys!

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