Hi,

I am new to UNIX programming i want to understand a simple thing.
Please help me out in deciphering the UNIX commands mentioned below.


All I need to understand is the meaning of -p & !-d in the second line.

I can easily get the meaning of special commands but can not understand what is -p & !-d in the second line.

The purpose of this command is to copy 1 file from 1 environment to another.


ksc_connect_dest_client
if [!-d [P.P_SUB_PATH]]; then mkdir -p [P.P_SUB_PATH]; fi
ksc_exit
ksc_copy_cliet_client SUB_PATH="[P.P_SUB_PATH]"FILENAME="[P.P_FILENAME]"
FILE_TYPE=[P.P FILE_TYPE]"

ksc_connect_dest_client
This command initiates a TELNET, SSH, or SSH2 session with the client of
the destination environment.

ksc_copy_client_client
This command copies a file from the source client environment to the
destination client environment.


ksc_exit
This command exits the TELNET, SSH, or SSH2 session initiated


[P.P_SUB_PATH]
The sub-directory that should be used to locate the file relative to the base path of each
environment


[P.P_FILE_TYPE]
Variable for that particular file type


[P.P_FILENAME]
Variable for that particular file name


please help me with this, i need urgent solution for this.

thanks.

Himanshu

Hi,

Firstly you need to remove your e-mail address from the bottom of your posts. The information that is posted on this forum is for the benefit of everyone and therefore replies shouldn't be e-mailed.

As for your questions.

mkdir -p ~ This will print no error message if the directory already exists and will make any parent directories if required.

!-d ~ This will test to see if the directory does NOT exist in the statement.

So what the second line of your code is doing essientially is seeing if a directory doesn't exist. If it doesn't then it creates the directory.

Hope this helps.

Thank You very much for your response _Spare_Ribs_ ,
I am sorry for posting my email id, i now have clear idea about the commands.


Himanshu