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12-27-2006
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Printing outputs using awk.
I have a output of a command like this.
the command is : bdf|sed '/^e/d'|awk '{print$2/1048576}' output : 0 0.515625 0.481979 2 2 2 7.8125 4 2 0.488281 7.8125 3.90625 4 1.95312 1 0.488281 15.625 7.8125 5.85938 0.20417 0.00119781 0.000595093 0.000587463 0.000587463 0.835808 0.206657 0.72831 0.000587463 0.000602722 0.000587463 1.73286 79.8446 6.20604 0.00723267 4.98518 i want to print only 2 digits after . please let me know how to do that? thanks. |
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01-09-2007
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Code:
sed 's/^.*\.\(..\)\(.*\)/\1/' filename |
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