remove line 1 and save it....

happyv · #1 (**permalink**) 12-19-2006

Hi,

I have txt file like below:

[0000.0217] report date
[0000.0288] 1234567
[0000.0291] 2345234
[0000.1312] 8976542

How can I skip to read line 1 and grep the number 288, 291 and 1312 and save into another new txt file?

vgersh99 · #2 (**permalink**) 12-19-2006

assuming you don't want these numbers ANYWHERE on the line, but rather as a second pair of numbers separated by '.' and enclosed inside the '[]'.

one 'ugly' way (that works for most sed-s):

Code:

sed -n '2,$s/.*288].*/&/p;2,$s/.*291].*/&/p;2,$s/.*1312].*/&/p' happy.txt

the 'saving' part is left as an exercise to the OP.

happyv · #3 (**permalink**) 12-19-2006

Quote:

Originally Posted by vgersh99

assuming you don't want these numbers ANYWHERE on the line, but rather as a second pair of numbers separated by '.' and enclosed inside the '[]'.

one 'ugly' way (that works for most sed-s):

Code:

sed -n '2,$s/.*288].*/&/p;2,$s/.*291].*/&/p;2,$s/.*1312].*/&/p' happy.txt

the 'saving' part is left as an exercise to the OP.

thank you for the suggestion. However, the number like 288, 291, 1312 is not the same everyday (because of the txt file created from someone and i only need the thesee number). How can I do it?

ghostdog74 · #4 (**permalink**) 12-19-2006

if you have Python installed and assume only a dot in each line.

Code:

#!/usr/bin/python
f=open("file")
f.readline()
for line in f:
     whereisdot = line.index(".")
     whereisclosebracket = line.index("]")
     print line[whereisdot + 1: whereisclosebracket ]

happyv · #5 (**permalink**) 12-20-2006

Quote:

Originally Posted by ghostdog74

if you have Python installed and assume only a dot in each line.

Code:

#!/usr/bin/python
for line in open("file"):
     whereisdot = line.index(".")
     whereisclosebracket = line.index("]")
     print line[whereisdot + 1: whereisclosebracket ]

Sorry, the server haven't Python installed. any suggestion?
and the first line should not be read as well..

cskumar · #6 (**permalink**) 12-20-2006

awk 'FNR == 1 {next} match($0 ,("288|291|1312")) {print substr($0,RSTART,RLENGTH)}' File > file1.txt

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